8j^2-1152=0

Solution for 8j^2-1152=0 equation:

8j^2-1152=0

a = 8; b = 0; c = -1152;
Δ = b2-4ac
Δ = 02-4·8·(-1152)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192}{2*8}=\frac{-192}{16}
=-12
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192}{2*8}=\frac{192}{16}
=12
$